A projectile is thrown with an initial velocity u at an angle θ with the horizontal. At the highest point of its trajectory, what are its velocity and acceleration?

Question

Think Extraordinary · Accepted Answer

Correct Answer: Option A. Velocity is u cos θ, Acceleration is g downwards. Explanation: At the peak of trajectory, the vertical component of velocity becomes zero (vy = 0), leaving only the horizontal component vx = u cos θ. The acceleration is always acceleration due to gravity g acting vertically downwards.

Answer

Option B: Velocity is 0, Acceleration is g downwards

Answer

Option C: Velocity is u cos θ, Acceleration is 0

Answer

Option D: Velocity is u sin θ, Acceleration is g

Mechanics - Projectile Motion

A projectile is thrown with an initial velocity u at an angle θ with the horizontal. At the highest point of its trajectory, what are its velocity and acceleration?